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111445113001 = 211528175891
BaseRepresentation
bin110011111001010100…
…1010111100010101001
3101122122210122022201211
41213302221113202221
53311214422104001
6123110331313121
711023466554615
oct1476251274251
9348583568654
10111445113001
1143299951982
12197228ab7a1
13a680a12561
1455730ba345
152d73dee351
hex19f2a578a9

111445113001 has 4 divisors (see below), whose sum is σ = 111973289104. Its totient is φ = 110916936900.

The previous prime is 111445112981. The next prime is 111445113019. The reversal of 111445113001 is 100311544111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 111445113001 - 213 = 111445104809 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (111445143001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 264087735 + ... + 264088156.

It is an arithmetic number, because the mean of its divisors is an integer number (27993322276).

Almost surely, 2111445113001 is an apocalyptic number.

It is an amenable number.

111445113001 is a deficient number, since it is larger than the sum of its proper divisors (528176103).

111445113001 is an equidigital number, since it uses as much as digits as its factorization.

111445113001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 528176102.

The product of its (nonzero) digits is 240, while the sum is 22.

Adding to 111445113001 its reverse (100311544111), we get a palindrome (211756657112).

The spelling of 111445113001 in words is "one hundred eleven billion, four hundred forty-five million, one hundred thirteen thousand, one".

Divisors: 1 211 528175891 111445113001