Base | Representation |
---|---|
bin | 10000001101111101011… |
… | …111110110101010110011 |
3 | 10221112201120012022210221 |
4 | 100031331133312222303 |
5 | 121230000010011201 |
6 | 2211554542233511 |
7 | 143343253652242 |
oct | 20157537665263 |
9 | 3845646168727 |
10 | 1114502032051 |
11 | 39a726384351 |
12 | 15bbb8585897 |
13 | 81135401125 |
14 | 3bd29504959 |
15 | 1decdbee4a1 |
hex | 1037d7f6ab3 |
1114502032051 has 2 divisors, whose sum is σ = 1114502032052. Its totient is φ = 1114502032050.
The previous prime is 1114502032019. The next prime is 1114502032067. The reversal of 1114502032051 is 1502302054111.
It is a strong prime.
It is an emirp because it is prime and its reverse (1502302054111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1114502032051 - 25 = 1114502032019 is a prime.
It is a super-2 number, since 2×11145020320512 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1114502032081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 557251016025 + 557251016026.
It is an arithmetic number, because the mean of its divisors is an integer number (557251016026).
Almost surely, 21114502032051 is an apocalyptic number.
1114502032051 is a deficient number, since it is larger than the sum of its proper divisors (1).
1114502032051 is an equidigital number, since it uses as much as digits as its factorization.
1114502032051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1200, while the sum is 25.
Adding to 1114502032051 its reverse (1502302054111), we get a palindrome (2616804086162).
The spelling of 1114502032051 in words is "one trillion, one hundred fourteen billion, five hundred two million, thirty-two thousand, fifty-one".
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