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1114502032051 is a prime number
BaseRepresentation
bin10000001101111101011…
…111110110101010110011
310221112201120012022210221
4100031331133312222303
5121230000010011201
62211554542233511
7143343253652242
oct20157537665263
93845646168727
101114502032051
1139a726384351
1215bbb8585897
1381135401125
143bd29504959
151decdbee4a1
hex1037d7f6ab3

1114502032051 has 2 divisors, whose sum is σ = 1114502032052. Its totient is φ = 1114502032050.

The previous prime is 1114502032019. The next prime is 1114502032067. The reversal of 1114502032051 is 1502302054111.

It is a strong prime.

It is an emirp because it is prime and its reverse (1502302054111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1114502032051 - 25 = 1114502032019 is a prime.

It is a super-2 number, since 2×11145020320512 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1114502032081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 557251016025 + 557251016026.

It is an arithmetic number, because the mean of its divisors is an integer number (557251016026).

Almost surely, 21114502032051 is an apocalyptic number.

1114502032051 is a deficient number, since it is larger than the sum of its proper divisors (1).

1114502032051 is an equidigital number, since it uses as much as digits as its factorization.

1114502032051 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1200, while the sum is 25.

Adding to 1114502032051 its reverse (1502302054111), we get a palindrome (2616804086162).

The spelling of 1114502032051 in words is "one trillion, one hundred fourteen billion, five hundred two million, thirty-two thousand, fifty-one".