Base | Representation |
---|---|
bin | 10100110000100101… |
… | …11001000110001001 |
3 | 1001202201022212121021 |
4 | 22120102321012021 |
5 | 140311111231011 |
6 | 5041524312441 |
7 | 543120065665 |
oct | 123022710611 |
9 | 31681285537 |
10 | 11145023881 |
11 | 47aa091442 |
12 | 21b0542721 |
13 | 1087ca35b4 |
14 | 77a2618a5 |
15 | 453689471 |
hex | 2984b9189 |
11145023881 has 2 divisors, whose sum is σ = 11145023882. Its totient is φ = 11145023880.
The previous prime is 11145023873. The next prime is 11145023887. The reversal of 11145023881 is 18832054111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7711649856 + 3433374025 = 87816^2 + 58595^2 .
It is a cyclic number.
It is not a de Polignac number, because 11145023881 - 23 = 11145023873 is a prime.
It is a super-2 number, since 2×111450238812 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11145023887) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5572511940 + 5572511941.
It is an arithmetic number, because the mean of its divisors is an integer number (5572511941).
Almost surely, 211145023881 is an apocalyptic number.
It is an amenable number.
11145023881 is a deficient number, since it is larger than the sum of its proper divisors (1).
11145023881 is an equidigital number, since it uses as much as digits as its factorization.
11145023881 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7680, while the sum is 34.
Adding to 11145023881 its reverse (18832054111), we get a palindrome (29977077992).
The spelling of 11145023881 in words is "eleven billion, one hundred forty-five million, twenty-three thousand, eight hundred eighty-one".
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