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11148539979914 = 25574269989957
BaseRepresentation
bin1010001000111011100011…
…0000111110100010001010
31110110210022220211111010222
42202032320300332202022
52430124202213324124
635413322450510042
72230312133162261
oct242167060764212
943423286744128
1011148539979914
1136090841a4397
1213007b3595322
1362b3c236b8ac
142a784106d5d8
15144eebeda25e
hexa23b8c3e88a

11148539979914 has 4 divisors (see below), whose sum is σ = 16722809969874. Its totient is φ = 5574269989956.

The previous prime is 11148539979803. The next prime is 11148539979917. The reversal of 11148539979914 is 41997993584111.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 9761456694889 + 1387083285025 = 3124333^2 + 1177745^2 .

It is a super-3 number, since 3×111485399799143 (a number of 40 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (11148539979917) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2787134994977 + ... + 2787134994980.

Almost surely, 211148539979914 is an apocalyptic number.

11148539979914 is a deficient number, since it is larger than the sum of its proper divisors (5574269989960).

11148539979914 is an equidigital number, since it uses as much as digits as its factorization.

11148539979914 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5574269989959.

The product of its digits is 88179840, while the sum is 71.

The spelling of 11148539979914 in words is "eleven trillion, one hundred forty-eight billion, five hundred thirty-nine million, nine hundred seventy-nine thousand, nine hundred fourteen".

Divisors: 1 2 5574269989957 11148539979914