Base | Representation |
---|---|
bin | 1010001001000001110110… |
… | …0101101110111010100011 |
3 | 1110110221200210210012020112 |
4 | 2202100131211232322203 |
5 | 2430141133232444141 |
6 | 35414202354401535 |
7 | 2230402063135505 |
oct | 242203545567243 |
9 | 43427623705215 |
10 | 11150231531171 |
11 | 3609872016937 |
12 | 1300ba5b902ab |
13 | 62b60194a6b5 |
14 | 2a7961995d75 |
15 | 14509a7707eb |
hex | a241d96eea3 |
11150231531171 has 2 divisors, whose sum is σ = 11150231531172. Its totient is φ = 11150231531170.
The previous prime is 11150231531093. The next prime is 11150231531177. The reversal of 11150231531171 is 17113513205111.
11150231531171 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (17113513205111) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11150231531171 is a prime.
It is not a weakly prime, because it can be changed into another prime (11150231531177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5575115765585 + 5575115765586.
It is an arithmetic number, because the mean of its divisors is an integer number (5575115765586).
Almost surely, 211150231531171 is an apocalyptic number.
11150231531171 is a deficient number, since it is larger than the sum of its proper divisors (1).
11150231531171 is an equidigital number, since it uses as much as digits as its factorization.
11150231531171 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3150, while the sum is 32.
Adding to 11150231531171 its reverse (17113513205111), we get a palindrome (28263744736282).
The spelling of 11150231531171 in words is "eleven trillion, one hundred fifty billion, two hundred thirty-one million, five hundred thirty-one thousand, one hundred seventy-one".
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