Base | Representation |
---|---|
bin | 10000001110100001001… |
… | …001000011010111010001 |
3 | 10221121021020102222222021 |
4 | 100032201021003113101 |
5 | 121232211102101023 |
6 | 2212134143411441 |
7 | 143364134621533 |
oct | 20164111032721 |
9 | 3847236388867 |
10 | 1115100034513 |
11 | 39aa02998463 |
12 | 1601448b3b81 |
13 | 811cc27a73a |
14 | 3bd84acb853 |
15 | 1e01647535d |
hex | 103a12435d1 |
1115100034513 has 2 divisors, whose sum is σ = 1115100034514. Its totient is φ = 1115100034512.
The previous prime is 1115100034507. The next prime is 1115100034589. The reversal of 1115100034513 is 3154300015111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 982729220929 + 132370813584 = 991327^2 + 363828^2 .
It is a cyclic number.
It is not a de Polignac number, because 1115100034513 - 217 = 1115099903441 is a prime.
It is a super-2 number, since 2×11151000345132 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1115100034613) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 557550017256 + 557550017257.
It is an arithmetic number, because the mean of its divisors is an integer number (557550017257).
Almost surely, 21115100034513 is an apocalyptic number.
It is an amenable number.
1115100034513 is a deficient number, since it is larger than the sum of its proper divisors (1).
1115100034513 is an equidigital number, since it uses as much as digits as its factorization.
1115100034513 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 900, while the sum is 25.
Adding to 1115100034513 its reverse (3154300015111), we get a palindrome (4269400049624).
The spelling of 1115100034513 in words is "one trillion, one hundred fifteen billion, one hundred million, thirty-four thousand, five hundred thirteen".
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