Base | Representation |
---|---|
bin | 10100110001010110… |
… | …00101001010010001 |
3 | 1001210011021000122101 |
4 | 22120223011022101 |
5 | 140314222133003 |
6 | 5042312240401 |
7 | 543225015334 |
oct | 123053051221 |
9 | 31704230571 |
10 | 11151364753 |
11 | 4802722431 |
12 | 21b26a0101 |
13 | 10893b37a9 |
14 | 77b03261b |
15 | 453edd11d |
hex | 298ac5291 |
11151364753 has 2 divisors, whose sum is σ = 11151364754. Its totient is φ = 11151364752.
The previous prime is 11151364739. The next prime is 11151364771. The reversal of 11151364753 is 35746315111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6160366144 + 4990998609 = 78488^2 + 70647^2 .
It is a cyclic number.
It is not a de Polignac number, because 11151364753 - 29 = 11151364241 is a prime.
It is not a weakly prime, because it can be changed into another prime (11151314753) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5575682376 + 5575682377.
It is an arithmetic number, because the mean of its divisors is an integer number (5575682377).
Almost surely, 211151364753 is an apocalyptic number.
It is an amenable number.
11151364753 is a deficient number, since it is larger than the sum of its proper divisors (1).
11151364753 is an equidigital number, since it uses as much as digits as its factorization.
11151364753 is an evil number, because the sum of its binary digits is even.
The product of its digits is 37800, while the sum is 37.
Adding to 11151364753 its reverse (35746315111), we get a palindrome (46897679864).
The spelling of 11151364753 in words is "eleven billion, one hundred fifty-one million, three hundred sixty-four thousand, seven hundred fifty-three".
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