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11155400281 is a prime number
BaseRepresentation
bin10100110001110100…
…11110011001011001
31001210102212001100101
422120322132121121
5140321240302111
65042534535401
7543304223614
oct123072363131
931712761311
1011155400281
114804a29383
1221b3b07561
13108a19758c
1477b7a317b
15454538bc1
hex298e9e659

11155400281 has 2 divisors, whose sum is σ = 11155400282. Its totient is φ = 11155400280.

The previous prime is 11155400203. The next prime is 11155400299. The reversal of 11155400281 is 18200455111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7196977225 + 3958423056 = 84835^2 + 62916^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11155400281 is a prime.

It is a super-2 number, since 2×111554002812 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11155406281) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5577700140 + 5577700141.

It is an arithmetic number, because the mean of its divisors is an integer number (5577700141).

Almost surely, 211155400281 is an apocalyptic number.

It is an amenable number.

11155400281 is a deficient number, since it is larger than the sum of its proper divisors (1).

11155400281 is an equidigital number, since it uses as much as digits as its factorization.

11155400281 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1600, while the sum is 28.

Adding to 11155400281 its reverse (18200455111), we get a palindrome (29355855392).

The spelling of 11155400281 in words is "eleven billion, one hundred fifty-five million, four hundred thousand, two hundred eighty-one".