Base | Representation |
---|---|
bin | 10100110001110110… |
… | …00000111111001011 |
3 | 1001210110010020200212 |
4 | 22120323000333023 |
5 | 140321304320323 |
6 | 5042541551335 |
7 | 543305353646 |
oct | 123073007713 |
9 | 31713106625 |
10 | 11155541963 |
11 | 4805015875 |
12 | 21b3b7554b |
13 | 108a216c07 |
14 | 77b7dca5d |
15 | 454565b78 |
hex | 298ec0fcb |
11155541963 has 2 divisors, whose sum is σ = 11155541964. Its totient is φ = 11155541962.
The previous prime is 11155541897. The next prime is 11155541977. The reversal of 11155541963 is 36914555111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11155541963 - 216 = 11155476427 is a prime.
It is a super-2 number, since 2×111555419632 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 11155541963.
It is not a weakly prime, because it can be changed into another prime (11155541993) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5577770981 + 5577770982.
It is an arithmetic number, because the mean of its divisors is an integer number (5577770982).
Almost surely, 211155541963 is an apocalyptic number.
11155541963 is a deficient number, since it is larger than the sum of its proper divisors (1).
11155541963 is an equidigital number, since it uses as much as digits as its factorization.
11155541963 is an evil number, because the sum of its binary digits is even.
The product of its digits is 81000, while the sum is 41.
The spelling of 11155541963 in words is "eleven billion, one hundred fifty-five million, five hundred forty-one thousand, nine hundred sixty-three".
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