Base | Representation |
---|---|
bin | 1010001001010111100001… |
… | …1011111011100101111011 |
3 | 1110111111201100111100021221 |
4 | 2202111320123323211323 |
5 | 2430240042431434421 |
6 | 35421004030412511 |
7 | 2230666222651051 |
oct | 242257033734573 |
9 | 43444640440257 |
10 | 11156050655611 |
11 | 3611288837194 |
12 | 130214a961137 |
13 | 62c01b3c6bb4 |
14 | 2a7d547601d1 |
15 | 1452db57a841 |
hex | a25786fb97b |
11156050655611 has 2 divisors, whose sum is σ = 11156050655612. Its totient is φ = 11156050655610.
The previous prime is 11156050655591. The next prime is 11156050655627. The reversal of 11156050655611 is 11655605065111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11156050655611 - 25 = 11156050655579 is a prime.
It is a super-3 number, since 3×111560506556113 (a number of 40 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (11156050655641) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5578025327805 + 5578025327806.
It is an arithmetic number, because the mean of its divisors is an integer number (5578025327806).
Almost surely, 211156050655611 is an apocalyptic number.
11156050655611 is a deficient number, since it is larger than the sum of its proper divisors (1).
11156050655611 is an equidigital number, since it uses as much as digits as its factorization.
11156050655611 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 135000, while the sum is 43.
The spelling of 11156050655611 in words is "eleven trillion, one hundred fifty-six billion, fifty million, six hundred fifty-five thousand, six hundred eleven".
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