Base | Representation |
---|---|
bin | 10100110010100001… |
… | …11111000010001011 |
3 | 1001210211221211210101 |
4 | 22121100333002023 |
5 | 140324243114011 |
6 | 5043305230231 |
7 | 543405331351 |
oct | 123120770213 |
9 | 31724854711 |
10 | 11161301131 |
11 | 4808299812 |
12 | 21b5a92377 |
13 | 108b4823c6 |
14 | 77c49b7d1 |
15 | 454d022c1 |
hex | 29943f08b |
11161301131 has 2 divisors, whose sum is σ = 11161301132. Its totient is φ = 11161301130.
The previous prime is 11161301113. The next prime is 11161301161. The reversal of 11161301131 is 13110316111.
Together with previous prime (11161301113) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11161301131 - 225 = 11127746699 is a prime.
It is a super-2 number, since 2×111613011312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11161301099 and 11161301108.
It is not a weakly prime, because it can be changed into another prime (11161301161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5580650565 + 5580650566.
It is an arithmetic number, because the mean of its divisors is an integer number (5580650566).
Almost surely, 211161301131 is an apocalyptic number.
11161301131 is a deficient number, since it is larger than the sum of its proper divisors (1).
11161301131 is an equidigital number, since it uses as much as digits as its factorization.
11161301131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 19.
Adding to 11161301131 its reverse (13110316111), we get a palindrome (24271617242).
The spelling of 11161301131 in words is "eleven billion, one hundred sixty-one million, three hundred one thousand, one hundred thirty-one".
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