Base | Representation |
---|---|
bin | 10000010000101010111… |
… | …110010100110010110011 |
3 | 10221211020101201022021012 |
4 | 100100222332110302303 |
5 | 121301430043300011 |
6 | 2213155431221135 |
7 | 143505344230625 |
oct | 20205276246263 |
9 | 3854211638235 |
10 | 1117412478131 |
11 | 3a098a238594 |
12 | 16068b2177ab |
13 | 814aa38b781 |
14 | 3c123c78c15 |
15 | 1e0ee4a3a8b |
hex | 1042af94cb3 |
1117412478131 has 2 divisors, whose sum is σ = 1117412478132. Its totient is φ = 1117412478130.
The previous prime is 1117412478053. The next prime is 1117412478137. The reversal of 1117412478131 is 1318742147111.
It is a strong prime.
It is an emirp because it is prime and its reverse (1318742147111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1117412478131 - 226 = 1117345369267 is a prime.
It is a super-2 number, since 2×11174124781312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1117412478137) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 558706239065 + 558706239066.
It is an arithmetic number, because the mean of its divisors is an integer number (558706239066).
Almost surely, 21117412478131 is an apocalyptic number.
1117412478131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1117412478131 is an equidigital number, since it uses as much as digits as its factorization.
1117412478131 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 37632, while the sum is 41.
The spelling of 1117412478131 in words is "one trillion, one hundred seventeen billion, four hundred twelve million, four hundred seventy-eight thousand, one hundred thirty-one".
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