Base | Representation |
---|---|
bin | 10000010000110000111… |
… | …110111110011100110011 |
3 | 10221211111102110012101211 |
4 | 100100300332332130303 |
5 | 121302131401441201 |
6 | 2213213432340551 |
7 | 143511010265233 |
oct | 20206076763463 |
9 | 3854442405354 |
10 | 1117513312051 |
11 | 3a0a31149604 |
12 | 1606b8b44757 |
13 | 814c5234a06 |
14 | 3c133405cc3 |
15 | 1e108270651 |
hex | 10430fbe733 |
1117513312051 has 4 divisors (see below), whose sum is σ = 1117845809704. Its totient is φ = 1117180814400.
The previous prime is 1117513312001. The next prime is 1117513312073. The reversal of 1117513312051 is 1502133157111.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1117513312051 - 215 = 1117513279283 is a prime.
It is a super-2 number, since 2×11175133120512 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1117513312001) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 166243785 + ... + 166250506.
It is an arithmetic number, because the mean of its divisors is an integer number (279461452426).
Almost surely, 21117513312051 is an apocalyptic number.
1117513312051 is a deficient number, since it is larger than the sum of its proper divisors (332497653).
1117513312051 is an equidigital number, since it uses as much as digits as its factorization.
1117513312051 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 332497652.
The product of its (nonzero) digits is 3150, while the sum is 31.
Adding to 1117513312051 its reverse (1502133157111), we get a palindrome (2619646469162).
The spelling of 1117513312051 in words is "one trillion, one hundred seventeen billion, five hundred thirteen million, three hundred twelve thousand, fifty-one".
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