Base | Representation |
---|---|
bin | 10100110100011100… |
… | …11001011010111001 |
3 | 1001211222020202021112 |
4 | 22122032121122321 |
5 | 140342403244433 |
6 | 5045042250105 |
7 | 543662221664 |
oct | 123216313271 |
9 | 31758222245 |
10 | 11177399993 |
11 | 4816395061 |
12 | 21bb356935 |
13 | 10918cac66 |
14 | 78068c6db |
15 | 456432348 |
hex | 29a3996b9 |
11177399993 has 2 divisors, whose sum is σ = 11177399994. Its totient is φ = 11177399992.
The previous prime is 11177399941. The next prime is 11177400019. The reversal of 11177399993 is 39999377111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9692993209 + 1484406784 = 98453^2 + 38528^2 .
It is an emirp because it is prime and its reverse (39999377111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11177399993 - 222 = 11173205689 is a prime.
It is a super-3 number, since 3×111773999933 (a number of 31 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (11177399393) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5588699996 + 5588699997.
It is an arithmetic number, because the mean of its divisors is an integer number (5588699997).
Almost surely, 211177399993 is an apocalyptic number.
It is an amenable number.
11177399993 is a deficient number, since it is larger than the sum of its proper divisors (1).
11177399993 is an equidigital number, since it uses as much as digits as its factorization.
11177399993 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2893401, while the sum is 59.
The spelling of 11177399993 in words is "eleven billion, one hundred seventy-seven million, three hundred ninety-nine thousand, nine hundred ninety-three".
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