Base | Representation |
---|---|
bin | 110100001000010011… |
… | …1101110101101010011 |
3 | 101200221211220122010022 |
4 | 1220100213232231103 |
5 | 3313232142000313 |
6 | 123232254054055 |
7 | 11042114204663 |
oct | 1502047565523 |
9 | 350854818108 |
10 | 111948000083 |
11 | 43527800437 |
12 | 198431aa32b |
13 | a730c6878a |
14 | 55bdbc41a3 |
15 | 2da3137c08 |
hex | 1a109eeb53 |
111948000083 has 2 divisors, whose sum is σ = 111948000084. Its totient is φ = 111948000082.
The previous prime is 111948000053. The next prime is 111948000089. The reversal of 111948000083 is 380000849111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 111948000083 - 216 = 111947934547 is a prime.
It is not a weakly prime, because it can be changed into another prime (111948000089) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55974000041 + 55974000042.
It is an arithmetic number, because the mean of its divisors is an integer number (55974000042).
Almost surely, 2111948000083 is an apocalyptic number.
111948000083 is a deficient number, since it is larger than the sum of its proper divisors (1).
111948000083 is an equidigital number, since it uses as much as digits as its factorization.
111948000083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 35.
Adding to 111948000083 its reverse (380000849111), we get a palindrome (491948849194).
The spelling of 111948000083 in words is "one hundred eleven billion, nine hundred forty-eight million, eighty-three", and thus it is an aban number.
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