1119998953 has 2 divisors, whose sum is σ = 1119998954. Its totient is φ = 1119998952.

The previous prime is 1119998933. The next prime is 1119998993. The reversal of 1119998953 is 3598999111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1028356624 + 91642329 = 32068^2 + 9573^2 .

It is an emirp because it is prime and its reverse (3598999111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1119998953 - 2⁵ = 1119998921 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1119998894 and 1119998903.

It is not a weakly prime, because it can be changed into another prime (1119998933) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 559999476 + 559999477.

It is an arithmetic number, because the mean of its divisors is an integer number (559999477).

Almost surely, 2^1119998953 is an apocalyptic number.

It is an amenable number.

1119998953 is a deficient number, since it is larger than the sum of its proper divisors (1).

1119998953 is an equidigital number, since it uses as much as digits as its factorization.

1119998953 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 787320, while the sum is 55.

The square root of 1119998953 is about 33466.3854188049. The cubic root of 1119998953 is about 1038.4984967665.

The spelling of 1119998953 in words is "one billion, one hundred nineteen million, nine hundred ninety-eight thousand, nine hundred fifty-three".