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112000000003 is a prime number
BaseRepresentation
bin110100001001110111…
…0000110000000000011
3101201002110202111121021
41220103232012000003
53313334000000003
6123241352410311
711043315202153
oct1502356060003
9351073674537
10112000000003
1143554097781
12198586a6997
13a73b974268
1455c6a7c763
152da79aa2bd
hex1a13b86003

112000000003 has 2 divisors, whose sum is σ = 112000000004. Its totient is φ = 112000000002.

The previous prime is 111999999989. The next prime is 112000000031. The reversal of 112000000003 is 300000000211.

It is a weak prime.

It is an emirp because it is prime and its reverse (300000000211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 112000000003 - 25 = 111999999971 is a prime.

It is not a weakly prime, because it can be changed into another prime (112000000703) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56000000001 + 56000000002.

It is an arithmetic number, because the mean of its divisors is an integer number (56000000002).

Almost surely, 2112000000003 is an apocalyptic number.

112000000003 is a deficient number, since it is larger than the sum of its proper divisors (1).

112000000003 is an equidigital number, since it uses as much as digits as its factorization.

112000000003 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6, while the sum is 7.

Adding to 112000000003 its reverse (300000000211), we get a palindrome (412000000214).

The spelling of 112000000003 in words is "one hundred twelve billion, three", and thus it is an aban number.