Base | Representation |
---|---|
bin | 10000010011000101111… |
… | …011001001010110011011 |
3 | 10222001221120101110022111 |
4 | 100103011323021112123 |
5 | 121322241100111212 |
6 | 2214305414333151 |
7 | 143626641612133 |
oct | 20230573112633 |
9 | 3861846343274 |
10 | 1120012113307 |
11 | 3a1aa3703a0a |
12 | 16109595a1b7 |
13 | 81802b34639 |
14 | 3c2cd223ac3 |
15 | 1e202810ea7 |
hex | 104c5ec959b |
1120012113307 has 2 divisors, whose sum is σ = 1120012113308. Its totient is φ = 1120012113306.
The previous prime is 1120012113299. The next prime is 1120012113331. The reversal of 1120012113307 is 7033112100211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1120012113307 - 23 = 1120012113299 is a prime.
It is not a weakly prime, because it can be changed into another prime (1120012113377) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560006056653 + 560006056654.
It is an arithmetic number, because the mean of its divisors is an integer number (560006056654).
Almost surely, 21120012113307 is an apocalyptic number.
1120012113307 is a deficient number, since it is larger than the sum of its proper divisors (1).
1120012113307 is an equidigital number, since it uses as much as digits as its factorization.
1120012113307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 252, while the sum is 22.
Adding to 1120012113307 its reverse (7033112100211), we get a palindrome (8153124213518).
The spelling of 1120012113307 in words is "one trillion, one hundred twenty billion, twelve million, one hundred thirteen thousand, three hundred seven".
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