Base | Representation |
---|---|
bin | 1010001011111011101101… |
… | …0011100110111000001011 |
3 | 1110122201110202220210012002 |
4 | 2202332323103212320023 |
5 | 2432000322242020133 |
6 | 35453133133141215 |
7 | 2234116320036101 |
oct | 242767323467013 |
9 | 43581422823162 |
10 | 11200122220043 |
11 | 3628a44008909 |
12 | 130a7aa32a80b |
13 | 633222b66783 |
14 | 2aa13598dc71 |
15 | 14651a721ce8 |
hex | a2fbb4e6e0b |
11200122220043 has 2 divisors, whose sum is σ = 11200122220044. Its totient is φ = 11200122220042.
The previous prime is 11200122219977. The next prime is 11200122220051. The reversal of 11200122220043 is 34002222100211.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11200122220043 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11200122219997 and 11200122220024.
It is not a weakly prime, because it can be changed into another prime (11200125220043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5600061110021 + 5600061110022.
It is an arithmetic number, because the mean of its divisors is an integer number (5600061110022).
Almost surely, 211200122220043 is an apocalyptic number.
11200122220043 is a deficient number, since it is larger than the sum of its proper divisors (1).
11200122220043 is an equidigital number, since it uses as much as digits as its factorization.
11200122220043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 384, while the sum is 20.
Adding to 11200122220043 its reverse (34002222100211), we get a palindrome (45202344320254).
The spelling of 11200122220043 in words is "eleven trillion, two hundred billion, one hundred twenty-two million, two hundred twenty thousand, forty-three".
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