Base | Representation |
---|---|
bin | 1010001011111011101111… |
… | …0010011011100011100011 |
3 | 1110122201111100010021222121 |
4 | 2202332323302123203203 |
5 | 2432000331324101011 |
6 | 35453134022245111 |
7 | 2234116445521153 |
oct | 242767362334343 |
9 | 43581440107877 |
10 | 11200130300131 |
11 | 3628a48627573 |
12 | 130a7b0b86797 |
13 | 6332247354a6 |
14 | 2aa136a94763 |
15 | 14651b2bae71 |
hex | a2fbbc9b8e3 |
11200130300131 has 2 divisors, whose sum is σ = 11200130300132. Its totient is φ = 11200130300130.
The previous prime is 11200130300123. The next prime is 11200130300137. The reversal of 11200130300131 is 13100303100211.
It is a strong prime.
It is an emirp because it is prime and its reverse (13100303100211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11200130300131 - 23 = 11200130300123 is a prime.
It is a super-2 number, since 2×112001303001312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11200130300137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5600065150065 + 5600065150066.
It is an arithmetic number, because the mean of its divisors is an integer number (5600065150066).
Almost surely, 211200130300131 is an apocalyptic number.
11200130300131 is a deficient number, since it is larger than the sum of its proper divisors (1).
11200130300131 is an equidigital number, since it uses as much as digits as its factorization.
11200130300131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 11200130300131 its reverse (13100303100211), we get a palindrome (24300433400342).
The spelling of 11200130300131 in words is "eleven trillion, two hundred billion, one hundred thirty million, three hundred thousand, one hundred thirty-one".
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