Base | Representation |
---|---|
bin | 1010001011111011110001… |
… | …1011101101101010100011 |
3 | 1110122201112002111010002101 |
4 | 2202332330123231222203 |
5 | 2432000342111402321 |
6 | 35453135050231231 |
7 | 2234116636513336 |
oct | 242767433555243 |
9 | 43581462433071 |
10 | 11200141122211 |
11 | 3628a53749338 |
12 | 130a7b4725517 |
13 | 633226a542a2 |
14 | 2aa1382b061d |
15 | 14651c207791 |
hex | a2fbc6edaa3 |
11200141122211 has 2 divisors, whose sum is σ = 11200141122212. Its totient is φ = 11200141122210.
The previous prime is 11200141122187. The next prime is 11200141122239. The reversal of 11200141122211 is 11222114100211.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11200141122211 is a prime.
It is a super-3 number, since 3×112001411222113 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (11200141102211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5600070561105 + 5600070561106.
It is an arithmetic number, because the mean of its divisors is an integer number (5600070561106).
Almost surely, 211200141122211 is an apocalyptic number.
11200141122211 is a deficient number, since it is larger than the sum of its proper divisors (1).
11200141122211 is an equidigital number, since it uses as much as digits as its factorization.
11200141122211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64, while the sum is 19.
Adding to 11200141122211 its reverse (11222114100211), we get a palindrome (22422255222422).
The spelling of 11200141122211 in words is "eleven trillion, two hundred billion, one hundred forty-one million, one hundred twenty-two thousand, two hundred eleven".
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