Base | Representation |
---|---|
bin | 11001011101110101110111… |
… | …011011111010001000010011 |
3 | 112200120021101121120100211111 |
4 | 121131311313123322020103 |
5 | 104140014310142414413 |
6 | 1034112540311154151 |
7 | 32406603435564031 |
oct | 3135656733721023 |
9 | 480507347510744 |
10 | 112001865982483 |
11 | 327617a7512264 |
12 | 1068a866375957 |
13 | 4a659662b8879 |
14 | 1d92cc2561551 |
15 | ce365b42dd3d |
hex | 65dd776fa213 |
112001865982483 has 2 divisors, whose sum is σ = 112001865982484. Its totient is φ = 112001865982482.
The previous prime is 112001865982439. The next prime is 112001865982493. The reversal of 112001865982483 is 384289568100211.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-112001865982483 is a prime.
It is not a weakly prime, because it can be changed into another prime (112001865982493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56000932991241 + 56000932991242.
It is an arithmetic number, because the mean of its divisors is an integer number (56000932991242).
Almost surely, 2112001865982483 is an apocalyptic number.
112001865982483 is a deficient number, since it is larger than the sum of its proper divisors (1).
112001865982483 is an equidigital number, since it uses as much as digits as its factorization.
112001865982483 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6635520, while the sum is 58.
The spelling of 112001865982483 in words is "one hundred twelve trillion, one billion, eight hundred sixty-five million, nine hundred eighty-two thousand, four hundred eighty-three".
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