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112001913617057 is a prime number
BaseRepresentation
bin11001011101110101111010…
…010001100111101010100001
3112200120021111221012110011222
4121131311322101213222201
5104140014404341221212
61034112545132144425
732406604554510242
oct3135657221475241
9480507457173158
10112001913617057
1132761821397882
121068a87a308115
134a659731263c9
141d92cc8a00cc9
15ce36606dcc72
hex65dd7a467aa1

112001913617057 has 2 divisors, whose sum is σ = 112001913617058. Its totient is φ = 112001913617056.

The previous prime is 112001913616981. The next prime is 112001913617173. The reversal of 112001913617057 is 750716319100211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 94800912203776 + 17201001413281 = 9736576^2 + 4147409^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-112001913617057 is a prime.

It is a super-3 number, since 3×1120019136170573 (a number of 43 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 112001913616999 and 112001913617017.

It is not a weakly prime, because it can be changed into another prime (112001913607057) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56000956808528 + 56000956808529.

It is an arithmetic number, because the mean of its divisors is an integer number (56000956808529).

Almost surely, 2112001913617057 is an apocalyptic number.

It is an amenable number.

112001913617057 is a deficient number, since it is larger than the sum of its proper divisors (1).

112001913617057 is an equidigital number, since it uses as much as digits as its factorization.

112001913617057 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 79380, while the sum is 44.

The spelling of 112001913617057 in words is "one hundred twelve trillion, one billion, nine hundred thirteen million, six hundred seventeen thousand, fifty-seven".