Base | Representation |
---|---|
bin | 10100110111001011… |
… | …10011010001111001 |
3 | 1001220120100211020201 |
4 | 22123211303101321 |
5 | 140414234444231 |
6 | 5051221322201 |
7 | 544361041063 |
oct | 123345632171 |
9 | 31816324221 |
10 | 11200312441 |
11 | 482831456a |
12 | 2206b66361 |
13 | 1096590c16 |
14 | 783734733 |
15 | 45845b161 |
hex | 29b973479 |
11200312441 has 2 divisors, whose sum is σ = 11200312442. Its totient is φ = 11200312440.
The previous prime is 11200312433. The next prime is 11200312511. The reversal of 11200312441 is 14421300211.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9157724416 + 2042588025 = 95696^2 + 45195^2 .
It is an emirp because it is prime and its reverse (14421300211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11200312441 - 23 = 11200312433 is a prime.
It is not a weakly prime, because it can be changed into another prime (11200312421) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5600156220 + 5600156221.
It is an arithmetic number, because the mean of its divisors is an integer number (5600156221).
Almost surely, 211200312441 is an apocalyptic number.
It is an amenable number.
11200312441 is a deficient number, since it is larger than the sum of its proper divisors (1).
11200312441 is an equidigital number, since it uses as much as digits as its factorization.
11200312441 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 11200312441 its reverse (14421300211), we get a palindrome (25621612652).
The spelling of 11200312441 in words is "eleven billion, two hundred million, three hundred twelve thousand, four hundred forty-one".
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