Base | Representation |
---|---|
bin | 10100110111010001… |
… | …11011010111110001 |
3 | 1001220121220110111101 |
4 | 22123220323113301 |
5 | 140414442211032 |
6 | 5051251044401 |
7 | 544401023365 |
oct | 123350732761 |
9 | 31817813441 |
10 | 11201132017 |
11 | 48288242a9 |
12 | 22072a0701 |
13 | 10967b9c8a |
14 | 7838a92a5 |
15 | 45856dde7 |
hex | 29ba3b5f1 |
11201132017 has 2 divisors, whose sum is σ = 11201132018. Its totient is φ = 11201132016.
The previous prime is 11201132003. The next prime is 11201132021. The reversal of 11201132017 is 71023110211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6699258801 + 4501873216 = 81849^2 + 67096^2 .
It is a cyclic number.
It is not a de Polignac number, because 11201132017 - 27 = 11201131889 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11201131985 and 11201132003.
It is not a weakly prime, because it can be changed into another prime (11201132077) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5600566008 + 5600566009.
It is an arithmetic number, because the mean of its divisors is an integer number (5600566009).
Almost surely, 211201132017 is an apocalyptic number.
It is an amenable number.
11201132017 is a deficient number, since it is larger than the sum of its proper divisors (1).
11201132017 is an equidigital number, since it uses as much as digits as its factorization.
11201132017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 84, while the sum is 19.
Adding to 11201132017 its reverse (71023110211), we get a palindrome (82224242228).
The spelling of 11201132017 in words is "eleven billion, two hundred one million, one hundred thirty-two thousand, seventeen".
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