Base | Representation |
---|---|
bin | 1010001011111111011110… |
… | …0001001100010111100010 |
3 | 1110122211002011202222101011 |
4 | 2202333313201030113202 |
5 | 2432004404344230214 |
6 | 35453421301131134 |
7 | 2234153334406204 |
oct | 242776741142742 |
9 | 43584064688334 |
10 | 11201132414434 |
11 | 3629412264906 |
12 | 130aa306b9aaa |
13 | 633354232b31 |
14 | 2aa1cdbd2774 |
15 | 146579268ac4 |
hex | a2ff784c5e2 |
11201132414434 has 4 divisors (see below), whose sum is σ = 16801698621654. Its totient is φ = 5600566207216.
The previous prime is 11201132414419. The next prime is 11201132414447. The reversal of 11201132414434 is 43441423110211.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 11197757153025 + 3375261409 = 3346305^2 + 58097^2 .
It is a junction number, because it is equal to n+sod(n) for n = 11201132414396 and 11201132414405.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2800283103607 + ... + 2800283103610.
Almost surely, 211201132414434 is an apocalyptic number.
11201132414434 is a deficient number, since it is larger than the sum of its proper divisors (5600566207220).
11201132414434 is an equidigital number, since it uses as much as digits as its factorization.
11201132414434 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5600566207219.
The product of its (nonzero) digits is 9216, while the sum is 31.
Adding to 11201132414434 its reverse (43441423110211), we get a palindrome (54642555524645).
The spelling of 11201132414434 in words is "eleven trillion, two hundred one billion, one hundred thirty-two million, four hundred fourteen thousand, four hundred thirty-four".
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