Base | Representation |
---|---|
bin | 110100001010001101… |
… | …1111010001010100011 |
3 | 101201010022100200102102 |
4 | 1220110123322022203 |
5 | 3313400033311042 |
6 | 123242502041015 |
7 | 11043522243152 |
oct | 1502433721243 |
9 | 351108320372 |
10 | 112012010147 |
11 | 4355a950114 |
12 | 1986071916b |
13 | a7412baa5b |
14 | 55c84c7599 |
15 | 2da8a7db32 |
hex | 1a146fa2a3 |
112012010147 has 2 divisors, whose sum is σ = 112012010148. Its totient is φ = 112012010146.
The previous prime is 112012010113. The next prime is 112012010171. The reversal of 112012010147 is 741010210211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 112012010147 - 26 = 112012010083 is a prime.
It is not a weakly prime, because it can be changed into another prime (112012000147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56006005073 + 56006005074.
It is an arithmetic number, because the mean of its divisors is an integer number (56006005074).
Almost surely, 2112012010147 is an apocalyptic number.
112012010147 is a deficient number, since it is larger than the sum of its proper divisors (1).
112012010147 is an equidigital number, since it uses as much as digits as its factorization.
112012010147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 112, while the sum is 20.
Adding to 112012010147 its reverse (741010210211), we get a palindrome (853022220358).
The spelling of 112012010147 in words is "one hundred twelve billion, twelve million, ten thousand, one hundred forty-seven".
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