Base | Representation |
---|---|
bin | 10000010011001100111… |
… | …101011001000111001011 |
3 | 10222002020210110222011021 |
4 | 100103030331121013023 |
5 | 121323011304031132 |
6 | 2214325232213311 |
7 | 143632604055064 |
oct | 20231475310713 |
9 | 3862223428137 |
10 | 1120130142667 |
11 | 3a205429a138 |
12 | 16110939a237 |
13 | 8182141b5b3 |
14 | 3c300b8956b |
15 | 1e20cd77997 |
hex | 104ccf591cb |
1120130142667 has 2 divisors, whose sum is σ = 1120130142668. Its totient is φ = 1120130142666.
The previous prime is 1120130142661. The next prime is 1120130142727. The reversal of 1120130142667 is 7662410310211.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1120130142667 is a prime.
It is a super-2 number, since 2×11201301426672 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1120130142661) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560065071333 + 560065071334.
It is an arithmetic number, because the mean of its divisors is an integer number (560065071334).
Almost surely, 21120130142667 is an apocalyptic number.
1120130142667 is a deficient number, since it is larger than the sum of its proper divisors (1).
1120130142667 is an equidigital number, since it uses as much as digits as its factorization.
1120130142667 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12096, while the sum is 34.
Adding to 1120130142667 its reverse (7662410310211), we get a palindrome (8782540452878).
The spelling of 1120130142667 in words is "one trillion, one hundred twenty billion, one hundred thirty million, one hundred forty-two thousand, six hundred sixty-seven".
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