Base | Representation |
---|---|
bin | 10000010011001100111… |
… | …101011001001000001011 |
3 | 10222002020210110222020122 |
4 | 100103030331121020023 |
5 | 121323011304031411 |
6 | 2214325232213455 |
7 | 143632604055215 |
oct | 20231475311013 |
9 | 3862223428218 |
10 | 1120130142731 |
11 | 3a205429a196 |
12 | 16110939a28b |
13 | 8182141b632 |
14 | 3c300b895b5 |
15 | 1e20cd779db |
hex | 104ccf5920b |
1120130142731 has 2 divisors, whose sum is σ = 1120130142732. Its totient is φ = 1120130142730.
The previous prime is 1120130142727. The next prime is 1120130142799. The reversal of 1120130142731 is 1372410310211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1120130142731 - 22 = 1120130142727 is a prime.
It is a super-2 number, since 2×11201301427312 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1120130142731.
It is not a weakly prime, because it can be changed into another prime (1120130142331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560065071365 + 560065071366.
It is an arithmetic number, because the mean of its divisors is an integer number (560065071366).
Almost surely, 21120130142731 is an apocalyptic number.
1120130142731 is a deficient number, since it is larger than the sum of its proper divisors (1).
1120130142731 is an equidigital number, since it uses as much as digits as its factorization.
1120130142731 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1008, while the sum is 26.
Adding to 1120130142731 its reverse (1372410310211), we get a palindrome (2492540452942).
The spelling of 1120130142731 in words is "one trillion, one hundred twenty billion, one hundred thirty million, one hundred forty-two thousand, seven hundred thirty-one".
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