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1120131432353 is a prime number
BaseRepresentation
bin10000010011001101000…
…010010011111110100001
310222002020212220111021102
4100103031002103332201
5121323012121313403
62214325320004145
7143632621036103
oct20231502237641
93862225814242
101120131432353
113a2054aa009a
12161109900655
138182178061b
143c301003573
151e20d02eb88
hex104cd093fa1

1120131432353 has 2 divisors, whose sum is σ = 1120131432354. Its totient is φ = 1120131432352.

The previous prime is 1120131432323. The next prime is 1120131432377. The reversal of 1120131432353 is 3532341310211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1042865779264 + 77265653089 = 1021208^2 + 277967^2 .

It is a cyclic number.

It is not a de Polignac number, because 1120131432353 - 210 = 1120131431329 is a prime.

It is not a weakly prime, because it can be changed into another prime (1120131432323) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560065716176 + 560065716177.

It is an arithmetic number, because the mean of its divisors is an integer number (560065716177).

Almost surely, 21120131432353 is an apocalyptic number.

It is an amenable number.

1120131432353 is a deficient number, since it is larger than the sum of its proper divisors (1).

1120131432353 is an equidigital number, since it uses as much as digits as its factorization.

1120131432353 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6480, while the sum is 29.

Adding to 1120131432353 its reverse (3532341310211), we get a palindrome (4652472742564).

The spelling of 1120131432353 in words is "one trillion, one hundred twenty billion, one hundred thirty-one million, four hundred thirty-two thousand, three hundred fifty-three".