Base | Representation |
---|---|
bin | 110100001010011101… |
… | …0100000001101100011 |
3 | 101201010212110011000101 |
4 | 1220110322200031203 |
5 | 3313404111432212 |
6 | 123243350003231 |
7 | 11043650355433 |
oct | 1502472401543 |
9 | 351125404011 |
10 | 112020030307 |
11 | 43564428849 |
12 | 19863346517 |
13 | a742b68403 |
14 | 55c95b42c3 |
15 | 2da9615157 |
hex | 1a14ea0363 |
112020030307 has 2 divisors, whose sum is σ = 112020030308. Its totient is φ = 112020030306.
The previous prime is 112020030257. The next prime is 112020030313. The reversal of 112020030307 is 703030020211.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-112020030307 is a prime.
It is a super-3 number, since 3×1120200303073 (a number of 34 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (112020030107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56010015153 + 56010015154.
It is an arithmetic number, because the mean of its divisors is an integer number (56010015154).
Almost surely, 2112020030307 is an apocalyptic number.
112020030307 is a deficient number, since it is larger than the sum of its proper divisors (1).
112020030307 is an equidigital number, since it uses as much as digits as its factorization.
112020030307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 252, while the sum is 19.
Adding to 112020030307 its reverse (703030020211), we get a palindrome (815050050518).
The spelling of 112020030307 in words is "one hundred twelve billion, twenty million, thirty thousand, three hundred seven".
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