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11202054433 = 68316401251
BaseRepresentation
bin10100110111011000…
…11100100100100001
31001220200122022210221
422123230130210201
5140420211220213
65051322523041
7544411614553
oct123354344441
931820568727
1011202054433
1148292a4329
122207666481
131096a50a9b
14783a694d3
154586a238d
hex29bb1c921

11202054433 has 4 divisors (see below), whose sum is σ = 11218456368. Its totient is φ = 11185652500.

The previous prime is 11202054419. The next prime is 11202054463. The reversal of 11202054433 is 33445020211.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11202054433 - 233 = 2612119841 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11202054398 and 11202054407.

It is not an unprimeable number, because it can be changed into a prime (11202054463) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8199943 + ... + 8201308.

It is an arithmetic number, because the mean of its divisors is an integer number (2804614092).

Almost surely, 211202054433 is an apocalyptic number.

It is an amenable number.

11202054433 is a deficient number, since it is larger than the sum of its proper divisors (16401935).

11202054433 is an equidigital number, since it uses as much as digits as its factorization.

11202054433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16401934.

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 11202054433 its reverse (33445020211), we get a palindrome (44647074644).

The spelling of 11202054433 in words is "eleven billion, two hundred two million, fifty-four thousand, four hundred thirty-three".

Divisors: 1 683 16401251 11202054433