Base | Representation |
---|---|
bin | 10000010011010001101… |
… | …111010010010111101001 |
3 | 10222002110101100222000201 |
4 | 100103101233102113221 |
5 | 121323142321043423 |
6 | 2214341215032201 |
7 | 143634566464456 |
oct | 20232157222751 |
9 | 3862411328021 |
10 | 1120210331113 |
11 | 3a2095589985 |
12 | 16113020b661 |
13 | 81834c16693 |
14 | 3c30b6a082d |
15 | 1e214e172ad |
hex | 104d1bd25e9 |
1120210331113 has 2 divisors, whose sum is σ = 1120210331114. Its totient is φ = 1120210331112.
The previous prime is 1120210331083. The next prime is 1120210331131. The reversal of 1120210331113 is 3111330120211.
Together with next prime (1120210331131) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 896435920809 + 223774410304 = 946803^2 + 473048^2 .
It is a cyclic number.
It is not a de Polignac number, because 1120210331113 - 25 = 1120210331081 is a prime.
It is not a weakly prime, because it can be changed into another prime (1120210331153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560105165556 + 560105165557.
It is an arithmetic number, because the mean of its divisors is an integer number (560105165557).
Almost surely, 21120210331113 is an apocalyptic number.
It is an amenable number.
1120210331113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1120210331113 is an equidigital number, since it uses as much as digits as its factorization.
1120210331113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 19.
Adding to 1120210331113 its reverse (3111330120211), we get a palindrome (4231540451324).
The spelling of 1120210331113 in words is "one trillion, one hundred twenty billion, two hundred ten million, three hundred thirty-one thousand, one hundred thirteen".
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