Base | Representation |
---|---|
bin | 110100001010100011… |
… | …0010101011101110011 |
3 | 101201011002021201202121 |
4 | 1220111012111131303 |
5 | 3313410410211034 |
6 | 123243540255111 |
7 | 11044015624351 |
oct | 1502506253563 |
9 | 351132251677 |
10 | 112023132019 |
11 | 43566157147 |
12 | 198643a1497 |
13 | a7436b3146 |
14 | 55c9b807d1 |
15 | 2da9a291b4 |
hex | 1a15195773 |
112023132019 has 2 divisors, whose sum is σ = 112023132020. Its totient is φ = 112023132018.
The previous prime is 112023131993. The next prime is 112023132041. The reversal of 112023132019 is 910231320211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 112023132019 - 213 = 112023123827 is a prime.
It is a super-2 number, since 2×1120231320192 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 112023131984 and 112023132002.
It is not a weakly prime, because it can be changed into another prime (112023132079) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56011566009 + 56011566010.
It is an arithmetic number, because the mean of its divisors is an integer number (56011566010).
Almost surely, 2112023132019 is an apocalyptic number.
112023132019 is a deficient number, since it is larger than the sum of its proper divisors (1).
112023132019 is an equidigital number, since it uses as much as digits as its factorization.
112023132019 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 25.
The spelling of 112023132019 in words is "one hundred twelve billion, twenty-three million, one hundred thirty-two thousand, nineteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •