Base | Representation |
---|---|
bin | 11001011110001100110010… |
… | …001101110100000011001001 |
3 | 112200122121220121202201110212 |
4 | 121132030302031310003021 |
5 | 104140420204430312213 |
6 | 1034132130224250505 |
7 | 32411434320325325 |
oct | 3136146215640311 |
9 | 480577817681425 |
10 | 112026474463433 |
11 | 32771185346222 |
12 | 10693593770a35 |
13 | 4a6808868caba |
14 | 1d94178910985 |
15 | ce40eba659a8 |
hex | 65e3323740c9 |
112026474463433 has 2 divisors, whose sum is σ = 112026474463434. Its totient is φ = 112026474463432.
The previous prime is 112026474463307. The next prime is 112026474463493. The reversal of 112026474463433 is 334364474620211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 75057739706569 + 36968734756864 = 8663587^2 + 6080192^2 .
It is a cyclic number.
It is not a de Polignac number, because 112026474463433 - 218 = 112026474201289 is a prime.
It is not a weakly prime, because it can be changed into another prime (112026474463493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56013237231716 + 56013237231717.
It is an arithmetic number, because the mean of its divisors is an integer number (56013237231717).
Almost surely, 2112026474463433 is an apocalyptic number.
It is an amenable number.
112026474463433 is a deficient number, since it is larger than the sum of its proper divisors (1).
112026474463433 is an equidigital number, since it uses as much as digits as its factorization.
112026474463433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6967296, while the sum is 50.
The spelling of 112026474463433 in words is "one hundred twelve trillion, twenty-six billion, four hundred seventy-four million, four hundred sixty-three thousand, four hundred thirty-three".
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