1120342431433 has 4 divisors (see below), whose sum is σ = 1120693529088. Its totient is φ = 1119991333780.

The previous prime is 1120342431353. The next prime is 1120342431443. The reversal of 1120342431433 is 3341342430211.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1120342431433 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1120342431395 and 1120342431404.

It is not an unprimeable number, because it can be changed into a prime (1120342431443) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 175544041 + ... + 175550422.

It is an arithmetic number, because the mean of its divisors is an integer number (280173382272).

Almost surely, 2^{1120342431433} is an apocalyptic number.

It is an amenable number.

1120342431433 is a deficient number, since it is larger than the sum of its proper divisors (351097655).

1120342431433 is an equidigital number, since it uses as much as digits as its factorization.

1120342431433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 351097654.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 1120342431433 its reverse (3341342430211), we get a palindrome (4461684861644).

The spelling of 1120342431433 in words is "one trillion, one hundred twenty billion, three hundred forty-two million, four hundred thirty-one thousand, four hundred thirty-three".