Base | Representation |
---|---|
bin | 11001011110011100011110… |
… | …100010011101100111000011 |
3 | 112200201020101220112002122102 |
4 | 121132130132202131213003 |
5 | 104141204211443421121 |
6 | 1034143554220501015 |
7 | 32412602010616001 |
oct | 3136343642354703 |
9 | 480636356462572 |
10 | 112043324201411 |
11 | 32778341603809 |
12 | 106968b66aa76b |
13 | 4a698424c1c65 |
14 | 1d94cd6677a71 |
15 | ce4785e5a90b |
hex | 65e71e89d9c3 |
112043324201411 has 2 divisors, whose sum is σ = 112043324201412. Its totient is φ = 112043324201410.
The previous prime is 112043324201399. The next prime is 112043324201507. The reversal of 112043324201411 is 114102423340211.
It is a weak prime.
It is an emirp because it is prime and its reverse (114102423340211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 112043324201411 - 238 = 111768446294467 is a prime.
It is not a weakly prime, because it can be changed into another prime (112043324281411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56021662100705 + 56021662100706.
It is an arithmetic number, because the mean of its divisors is an integer number (56021662100706).
Almost surely, 2112043324201411 is an apocalyptic number.
112043324201411 is a deficient number, since it is larger than the sum of its proper divisors (1).
112043324201411 is an equidigital number, since it uses as much as digits as its factorization.
112043324201411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4608, while the sum is 29.
Adding to 112043324201411 its reverse (114102423340211), we get a palindrome (226145747541622).
The spelling of 112043324201411 in words is "one hundred twelve trillion, forty-three billion, three hundred twenty-four million, two hundred one thousand, four hundred eleven".
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