1120441300441 has 2 divisors, whose sum is σ = 1120441300442. Its totient is φ = 1120441300440.

The previous prime is 1120441300423. The next prime is 1120441300463. The reversal of 1120441300441 is 1440031440211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 996195625216 + 124245675225 = 998096^2 + 352485^2 .

It is a cyclic number.

It is not a de Polignac number, because 1120441300441 - 2¹¹ = 1120441298393 is a prime.

It is not a weakly prime, because it can be changed into another prime (1120441300411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560220650220 + 560220650221.

It is an arithmetic number, because the mean of its divisors is an integer number (560220650221).

Almost surely, 2^{1120441300441} is an apocalyptic number.

It is an amenable number.

1120441300441 is a deficient number, since it is larger than the sum of its proper divisors (1).

1120441300441 is an equidigital number, since it uses as much as digits as its factorization.

1120441300441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 1120441300441 its reverse (1440031440211), we get a palindrome (2560472740652).

The spelling of 1120441300441 in words is "one trillion, one hundred twenty billion, four hundred forty-one million, three hundred thousand, four hundred forty-one".