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11204434010443 = 43260568232801
BaseRepresentation
bin1010001100001011110001…
…0011110010000101001011
31110200010121021022102122211
42203002330103302011023
52432033140101313233
635455125041525551
72234331214456432
oct243027423620513
943603537272584
1011204434010443
11362a856999853
12130b5b23438b7
1363375c25373b
142aa4244a6119
151466be0345cd
hexa30bc4f214b

11204434010443 has 4 divisors (see below), whose sum is σ = 11465002243288. Its totient is φ = 10943865777600.

The previous prime is 11204434010431. The next prime is 11204434010449. The reversal of 11204434010443 is 34401043440211.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11204434010443 - 25 = 11204434010411 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11204434010449) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 130284116358 + ... + 130284116443.

It is an arithmetic number, because the mean of its divisors is an integer number (2866250560822).

Almost surely, 211204434010443 is an apocalyptic number.

11204434010443 is a deficient number, since it is larger than the sum of its proper divisors (260568232845).

11204434010443 is an equidigital number, since it uses as much as digits as its factorization.

11204434010443 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 260568232844.

The product of its (nonzero) digits is 18432, while the sum is 31.

Adding to 11204434010443 its reverse (34401043440211), we get a palindrome (45605477450654).

The spelling of 11204434010443 in words is "eleven trillion, two hundred four billion, four hundred thirty-four million, ten thousand, four hundred forty-three".

Divisors: 1 43 260568232801 11204434010443