Base | Representation |
---|---|
bin | 1010001100001110010000… |
… | …0001010000111011101001 |
3 | 1110200012022200221122021011 |
4 | 2203003210001100323221 |
5 | 2432041021130312323 |
6 | 35455315121343521 |
7 | 2234353554406414 |
oct | 243034401207351 |
9 | 43605280848234 |
10 | 11205100244713 |
11 | 3630068a76491 |
12 | 130b759497ba1 |
13 | 63383729cabb |
14 | 2aa488b70b7b |
15 | 14670c78720d |
hex | a30e4050ee9 |
11205100244713 has 2 divisors, whose sum is σ = 11205100244714. Its totient is φ = 11205100244712.
The previous prime is 11205100244699. The next prime is 11205100244729. The reversal of 11205100244713 is 31744200150211.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7625727606784 + 3579372637929 = 2761472^2 + 1891923^2 .
It is a cyclic number.
It is not a de Polignac number, because 11205100244713 - 237 = 11067661291241 is a prime.
It is not a weakly prime, because it can be changed into another prime (11205100244213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5602550122356 + 5602550122357.
It is an arithmetic number, because the mean of its divisors is an integer number (5602550122357).
Almost surely, 211205100244713 is an apocalyptic number.
It is an amenable number.
11205100244713 is a deficient number, since it is larger than the sum of its proper divisors (1).
11205100244713 is an equidigital number, since it uses as much as digits as its factorization.
11205100244713 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6720, while the sum is 31.
Adding to 11205100244713 its reverse (31744200150211), we get a palindrome (42949300394924).
The spelling of 11205100244713 in words is "eleven trillion, two hundred five billion, one hundred million, two hundred forty-four thousand, seven hundred thirteen".
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