Base | Representation |
---|---|
bin | 1010001100010100000001… |
… | …1101011100010101111001 |
3 | 1110200100022210020001021020 |
4 | 2203011000131130111321 |
5 | 2432102210142312403 |
6 | 35500133042333053 |
7 | 2234440155641442 |
oct | 243050035342571 |
9 | 43610283201236 |
10 | 11206651135353 |
11 | 3630794455593 |
12 | 130bb1095a189 |
13 | 633a2369c97b |
14 | 2aa594b202c9 |
15 | 14679d9d5453 |
hex | a314075c579 |
11206651135353 has 4 divisors (see below), whose sum is σ = 14942201513808. Its totient is φ = 7471100756900.
The previous prime is 11206651135319. The next prime is 11206651135399. The reversal of 11206651135353 is 35353115660211.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 11206651135353 - 221 = 11206649038201 is a prime.
It is not an unprimeable number, because it can be changed into a prime (11206651131353) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1867775189223 + ... + 1867775189228.
It is an arithmetic number, because the mean of its divisors is an integer number (3735550378452).
Almost surely, 211206651135353 is an apocalyptic number.
It is an amenable number.
11206651135353 is a deficient number, since it is larger than the sum of its proper divisors (3735550378455).
11206651135353 is an equidigital number, since it uses as much as digits as its factorization.
11206651135353 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3735550378454.
The product of its (nonzero) digits is 243000, while the sum is 42.
Adding to 11206651135353 its reverse (35353115660211), we get a palindrome (46559766795564).
The spelling of 11206651135353 in words is "eleven trillion, two hundred six billion, six hundred fifty-one million, one hundred thirty-five thousand, three hundred fifty-three".
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