Base | Representation |
---|---|
bin | 11001011111000111111110… |
… | …010111101011000001101001 |
3 | 112200212200221212002220200022 |
4 | 121133013332113223001221 |
5 | 104142440334430021441 |
6 | 1034221240513450225 |
7 | 32416144262224622 |
oct | 3137077627530151 |
9 | 480780855086608 |
10 | 112090029142121 |
11 | 327961292a6a68 |
12 | 106a396bb70975 |
13 | 4a710766bc454 |
14 | 1d97287516a49 |
15 | ce5abb3c684b |
hex | 65f1fe5eb069 |
112090029142121 has 2 divisors, whose sum is σ = 112090029142122. Its totient is φ = 112090029142120.
The previous prime is 112090029142109. The next prime is 112090029142127. The reversal of 112090029142121 is 121241920090211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 68292952242025 + 43797076900096 = 8263955^2 + 6617936^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-112090029142121 is a prime.
It is not a weakly prime, because it can be changed into another prime (112090029142127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56045014571060 + 56045014571061.
It is an arithmetic number, because the mean of its divisors is an integer number (56045014571061).
Almost surely, 2112090029142121 is an apocalyptic number.
It is an amenable number.
112090029142121 is a deficient number, since it is larger than the sum of its proper divisors (1).
112090029142121 is an equidigital number, since it uses as much as digits as its factorization.
112090029142121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 35.
The spelling of 112090029142121 in words is "one hundred twelve trillion, ninety billion, twenty-nine million, one hundred forty-two thousand, one hundred twenty-one".
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