Base | Representation |
---|---|
bin | 10000010100000000100… |
… | …111011101010001110001 |
3 | 10222011111012021010012122 |
4 | 100110000213131101301 |
5 | 121331300140322133 |
6 | 2214551232004025 |
7 | 143663226435422 |
oct | 20240047352161 |
9 | 3864435233178 |
10 | 1120996807793 |
11 | 3a2459523505 |
12 | 16130b690615 |
13 | 8192bb430b5 |
14 | 3c383d09649 |
15 | 1e25debc498 |
hex | 105009dd471 |
1120996807793 has 2 divisors, whose sum is σ = 1120996807794. Its totient is φ = 1120996807792.
The previous prime is 1120996807783. The next prime is 1120996807807. The reversal of 1120996807793 is 3977086990211.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1050987881329 + 70008926464 = 1025177^2 + 264592^2 .
It is an emirp because it is prime and its reverse (3977086990211) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1120996807793 is a prime.
It is not a weakly prime, because it can be changed into another prime (1120996807783) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560498403896 + 560498403897.
It is an arithmetic number, because the mean of its divisors is an integer number (560498403897).
Almost surely, 21120996807793 is an apocalyptic number.
It is an amenable number.
1120996807793 is a deficient number, since it is larger than the sum of its proper divisors (1).
1120996807793 is an equidigital number, since it uses as much as digits as its factorization.
1120996807793 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10287648, while the sum is 62.
The spelling of 1120996807793 in words is "one trillion, one hundred twenty billion, nine hundred ninety-six million, eight hundred seven thousand, seven hundred ninety-three".
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