Base | Representation |
---|---|
bin | 1010001100100000100010… |
… | …1110011000101101101001 |
3 | 1110200122222221102212201102 |
4 | 2203020020232120231221 |
5 | 2432131100310121022 |
6 | 35501450304331145 |
7 | 2234616344331056 |
oct | 243101056305551 |
9 | 43618887385642 |
10 | 11210011020137 |
11 | 3632158a81776 |
12 | 13106aa013ab5 |
13 | 63413a7bb687 |
14 | 2aa7d304802d |
15 | 1468e8966a92 |
hex | a3208b98b69 |
11210011020137 has 2 divisors, whose sum is σ = 11210011020138. Its totient is φ = 11210011020136.
The previous prime is 11210011020119. The next prime is 11210011020149. The reversal of 11210011020137 is 73102011001211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10480428547801 + 729582472336 = 3237349^2 + 854156^2 .
It is a cyclic number.
It is not a de Polignac number, because 11210011020137 - 224 = 11209994242921 is a prime.
It is not a weakly prime, because it can be changed into another prime (11210011020107) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5605005510068 + 5605005510069.
It is an arithmetic number, because the mean of its divisors is an integer number (5605005510069).
Almost surely, 211210011020137 is an apocalyptic number.
It is an amenable number.
11210011020137 is a deficient number, since it is larger than the sum of its proper divisors (1).
11210011020137 is an equidigital number, since it uses as much as digits as its factorization.
11210011020137 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 84, while the sum is 20.
Adding to 11210011020137 its reverse (73102011001211), we get a palindrome (84312022021348).
The spelling of 11210011020137 in words is "eleven trillion, two hundred ten billion, eleven million, twenty thousand, one hundred thirty-seven".
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