Base | Representation |
---|---|
bin | 10000010100000001011… |
… | …110110001111000110011 |
3 | 10222011112012112220200021 |
4 | 100110001132301320303 |
5 | 121331312343411011 |
6 | 2214552510504311 |
7 | 143663463626326 |
oct | 20240136617063 |
9 | 3864465486607 |
10 | 1121011310131 |
11 | 3a2466729309 |
12 | 161314505097 |
13 | 81931b5006b |
14 | 3c385c027bd |
15 | 1e2603d4471 |
hex | 105017b1e33 |
1121011310131 has 2 divisors, whose sum is σ = 1121011310132. Its totient is φ = 1121011310130.
The previous prime is 1121011310021. The next prime is 1121011310143. The reversal of 1121011310131 is 1310131101211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1121011310131 - 215 = 1121011277363 is a prime.
It is a super-2 number, since 2×11210113101312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1121011310161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560505655065 + 560505655066.
It is an arithmetic number, because the mean of its divisors is an integer number (560505655066).
Almost surely, 21121011310131 is an apocalyptic number.
1121011310131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1121011310131 is an equidigital number, since it uses as much as digits as its factorization.
1121011310131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18, while the sum is 16.
Adding to 1121011310131 its reverse (1310131101211), we get a palindrome (2431142411342).
The spelling of 1121011310131 in words is "one trillion, one hundred twenty-one billion, eleven million, three hundred ten thousand, one hundred thirty-one".
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