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112104113412227 is a prime number
BaseRepresentation
bin11001011111010101000101…
…110110111001100010000011
3112200221001022102010222002212
4121133111011312321202003
5104143203211013142402
61034231530240332335
732420153302442606
oct3137250566714203
9480831272128085
10112104113412227
11327a10a6522612
12106a66409140ab
134a724ac5c51a1
141d97c21c8833d
15ce6142b03952
hex65f545db9883

112104113412227 has 2 divisors, whose sum is σ = 112104113412228. Its totient is φ = 112104113412226.

The previous prime is 112104113412157. The next prime is 112104113412289. The reversal of 112104113412227 is 722214311401211.

It is a strong prime.

It is an emirp because it is prime and its reverse (722214311401211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 112104113412227 - 210 = 112104113411203 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 112104113412193 and 112104113412202.

It is not a weakly prime, because it can be changed into another prime (112104113412527) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56052056706113 + 56052056706114.

It is an arithmetic number, because the mean of its divisors is an integer number (56052056706114).

Almost surely, 2112104113412227 is an apocalyptic number.

112104113412227 is a deficient number, since it is larger than the sum of its proper divisors (1).

112104113412227 is an equidigital number, since it uses as much as digits as its factorization.

112104113412227 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5376, while the sum is 32.

Adding to 112104113412227 its reverse (722214311401211), we get a palindrome (834318424813438).

The spelling of 112104113412227 in words is "one hundred twelve trillion, one hundred four billion, one hundred thirteen million, four hundred twelve thousand, two hundred twenty-seven".