Base | Representation |
---|---|
bin | 10000010100000111010… |
… | …111010011010010011001 |
3 | 10222011210002021112200002 |
4 | 100110013113103102121 |
5 | 121332013130404311 |
6 | 2215010354222345 |
7 | 143666102610122 |
oct | 20240727232231 |
9 | 3864702245602 |
10 | 1121110013081 |
11 | 3a25074142a3 |
12 | 1613415849b5 |
13 | 8194942b386 |
14 | 3c394d77049 |
15 | 1e268dce93b |
hex | 105075d3499 |
1121110013081 has 2 divisors, whose sum is σ = 1121110013082. Its totient is φ = 1121110013080.
The previous prime is 1121110013041. The next prime is 1121110013143. The reversal of 1121110013081 is 1803100111211.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 686445390400 + 434664622681 = 828520^2 + 659291^2 .
It is a cyclic number.
It is not a de Polignac number, because 1121110013081 - 26 = 1121110013017 is a prime.
It is a super-2 number, since 2×11211100130812 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1121110013041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560555006540 + 560555006541.
It is an arithmetic number, because the mean of its divisors is an integer number (560555006541).
Almost surely, 21121110013081 is an apocalyptic number.
It is an amenable number.
1121110013081 is a deficient number, since it is larger than the sum of its proper divisors (1).
1121110013081 is an equidigital number, since it uses as much as digits as its factorization.
1121110013081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 20.
Adding to 1121110013081 its reverse (1803100111211), we get a palindrome (2924210124292).
The spelling of 1121110013081 in words is "one trillion, one hundred twenty-one billion, one hundred ten million, thirteen thousand, eighty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •