Base | Representation |
---|---|
bin | 10100111000011110… |
… | …00001111000000011 |
3 | 1001221022200220121112 |
4 | 22130033001320003 |
5 | 140430021321011 |
6 | 5052245113535 |
7 | 544551643301 |
oct | 123417017003 |
9 | 31838626545 |
10 | 11211120131 |
11 | 4833426542 |
12 | 220a6b88ab |
13 | 10988a62c3 |
14 | 784d49271 |
15 | 45939358b |
hex | 29c3c1e03 |
11211120131 has 2 divisors, whose sum is σ = 11211120132. Its totient is φ = 11211120130.
The previous prime is 11211120077. The next prime is 11211120229. The reversal of 11211120131 is 13102111211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11211120131 - 210 = 11211119107 is a prime.
It is a super-2 number, since 2×112111201312 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11211120331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5605560065 + 5605560066.
It is an arithmetic number, because the mean of its divisors is an integer number (5605560066).
Almost surely, 211211120131 is an apocalyptic number.
11211120131 is a deficient number, since it is larger than the sum of its proper divisors (1).
11211120131 is an equidigital number, since it uses as much as digits as its factorization.
11211120131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12, while the sum is 14.
Adding to 11211120131 its reverse (13102111211), we get a palindrome (24313231342).
The spelling of 11211120131 in words is "eleven billion, two hundred eleven million, one hundred twenty thousand, one hundred thirty-one".
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