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11211121001257 is a prime number
BaseRepresentation
bin1010001100100100101011…
…1000101000001100101001
31110200202212022001202120021
42203021022320220030221
52432140333434020012
635502152355200441
72234656013114452
oct243111270501451
943622768052507
1011211121001257
113632678593a41
1213109598a6121
13634286755438
142aa89a624129
15146961120007
hexa324ae28329

11211121001257 has 2 divisors, whose sum is σ = 11211121001258. Its totient is φ = 11211121001256.

The previous prime is 11211121001191. The next prime is 11211121001291. The reversal of 11211121001257 is 75210012111211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7011289677456 + 4199831323801 = 2647884^2 + 2049349^2 .

It is a cyclic number.

It is not a de Polignac number, because 11211121001257 - 235 = 11176761262889 is a prime.

It is not a weakly prime, because it can be changed into another prime (11211121001557) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5605560500628 + 5605560500629.

It is an arithmetic number, because the mean of its divisors is an integer number (5605560500629).

Almost surely, 211211121001257 is an apocalyptic number.

It is an amenable number.

11211121001257 is a deficient number, since it is larger than the sum of its proper divisors (1).

11211121001257 is an equidigital number, since it uses as much as digits as its factorization.

11211121001257 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 280, while the sum is 25.

Adding to 11211121001257 its reverse (75210012111211), we get a palindrome (86421133112468).

The spelling of 11211121001257 in words is "eleven trillion, two hundred eleven billion, one hundred twenty-one million, one thousand, two hundred fifty-seven".