Base | Representation |
---|---|
bin | 110100001101001011… |
… | …0010100111010100011 |
3 | 101201101020000120020111 |
4 | 1220122112110322203 |
5 | 3314100432211042 |
6 | 123300404152151 |
7 | 11046135364036 |
oct | 1503226247243 |
9 | 351336016214 |
10 | 112111210147 |
11 | 43600945592 |
12 | 19889998657 |
13 | a758a11391 |
14 | 55d774b01d |
15 | 2db2626517 |
hex | 1a1a594ea3 |
112111210147 has 2 divisors, whose sum is σ = 112111210148. Its totient is φ = 112111210146.
The previous prime is 112111210117. The next prime is 112111210157. The reversal of 112111210147 is 741012111211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 112111210147 - 215 = 112111177379 is a prime.
It is not a weakly prime, because it can be changed into another prime (112111210117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56055605073 + 56055605074.
It is an arithmetic number, because the mean of its divisors is an integer number (56055605074).
Almost surely, 2112111210147 is an apocalyptic number.
112111210147 is a deficient number, since it is larger than the sum of its proper divisors (1).
112111210147 is an equidigital number, since it uses as much as digits as its factorization.
112111210147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 112, while the sum is 22.
Adding to 112111210147 its reverse (741012111211), we get a palindrome (853123321358).
The spelling of 112111210147 in words is "one hundred twelve billion, one hundred eleven million, two hundred ten thousand, one hundred forty-seven".
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